Question

Give p(0),(1)and p (2) for p(t)=2+t+2t²-t³​

Answer 1

Answer:

p(t) = 2 + t + 2t^2 - t^3

p(0) = 2 + 0 + 2(0)^2 - (0)^3

= 2+0+0-0

= 2

p(1) = 2 + 1 + 2(1)^2 - (1)^3

= 2+1+2-1

= 4

p(2) = 2 + 2 + 2( 2)^2 -(2)^3

= 2 + 2 + 8 - 8

= 4