Question

Give possible expression for the length and breadth of rectangle whose area is 4a²+4a-3​

Answer 1

Answer:

(2a-1)(2a+3) = 0

Hope it helps u!!

Answer 2

Answer:

$\huge{\boxed{\rm{\red{(2a-1) and (2a+3)}}}}$

Step-by-step explanation:

Given:-

Area of a rectangle is 4a²+4a-3

To find:-

Give possible expression for the length and breadth of rectangle whose area is 4a²+4a-3.

Solution :-

Area of the given rectangle is 4a²+4a-3

Used formula:-

Area of a rectangle whose length and breadth are l and b units is "lb" sq.units

Now,

Area=4a²+4a-3

=>4a²-2a+6a-3

=>2a(2a-1)+3(2a-1)

=>(2a-1)(2a+3)

Area is in the form of lb

So, The possible values of length and breadth are (2a-1) and (2a+3) units

Answer:-

The possible values of length and breadth are (2a-1) and (2a+3) units