Question

give possible expression for the length and breadth of rectangle whose area is 4a2+4a-3

Answer 1

$4 {a}^{2} + 4a - 3 = 4 {a }^{2} + 6a - 2a - 3 \\ = 2a(2a + 3) - (2a + 3) \\ = (2a - 1)(2a + 3) \\ thus \: \: \: length = 2a + 3 \\ breadth = 2a - 1$

Answer 2

hi mate,

solution:

Factoring 4a²+4a-3

4a² - 2a + 6a - 3

Step-1 : Add up the first 2 terms, pulling out like factors :

2a • (2a-1)

Add up the last 2 terms, pulling out common factors :

3 • (2a-1)

Step-2 : Add up the four terms of step 1 :

(2a+3) • (2a-1)

Which is the desired factorization

Final result :

(2a - 1) • (2a + 3)

length = (2a - 1) and breadth = (2a + 3)

or a = 1/2 and a = 3/2

i hope it helps you.