give possible expression for the length and breadth of a rectangle havin A=35y²+13y-12
Answers
Answered by
0
Area of rectangle= lenght ×breadth
So, clearly lenght and breadth will be the factor of Area
35y²+13y-12
35y²+28y-15y-12
7y(5y+4)-3(5y+4)
(7y-3)(5y+4)
Hence (7y-3)and (5y+4) are the lenght breadth of the rectangle.
So, clearly lenght and breadth will be the factor of Area
35y²+13y-12
35y²+28y-15y-12
7y(5y+4)-3(5y+4)
(7y-3)(5y+4)
Hence (7y-3)and (5y+4) are the lenght breadth of the rectangle.
Answered by
5
Given Area:
35y²+13y-12
To Find :
Length and Breadth
Solution :
Factorising 35y²+13y-12
[By mid term spilting]
35y²+13y-12
35y²+28y-25y-12
7y(5y+4)-3(5y+4)
(5y+4) (7y-3)
Length = 7y-3
Breadth = 5y+4
35y²+13y-12
To Find :
Length and Breadth
Solution :
Factorising 35y²+13y-12
[By mid term spilting]
35y²+13y-12
35y²+28y-25y-12
7y(5y+4)-3(5y+4)
(5y+4) (7y-3)
Length = 7y-3
Breadth = 5y+4
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