give possible expression for the length and breadth of the rectangle in which their area is 25a^2+35a-12
Answers
Answered by
14
Let the dimensions of the rectangle are
Length =l
Breadth = b
Given area = 25a^2 +35a-12
l*b= 25a^2 -20a-15a-12
=5a(5a-4)-3(5a-4)
=(5a-4)(5a-3)
Therefore
l=5a-4, b=5a-3 units
Or
l=(5a-3) units, b=(5a-4) units
Length =l
Breadth = b
Given area = 25a^2 +35a-12
l*b= 25a^2 -20a-15a-12
=5a(5a-4)-3(5a-4)
=(5a-4)(5a-3)
Therefore
l=5a-4, b=5a-3 units
Or
l=(5a-3) units, b=(5a-4) units
mysticd:
:)
Answered by
6
Given Area:
25a²-35a+12
To Find :
Length and Breadth
Solution :
Factorising 25a²-35a+12
[By mid term spilting]
25a²-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-4)(5a-3)
Length = 5a-4
Breadth = 5a-3
25a²-35a+12
To Find :
Length and Breadth
Solution :
Factorising 25a²-35a+12
[By mid term spilting]
25a²-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-4)(5a-3)
Length = 5a-4
Breadth = 5a-3
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