Give possible expression for the length and breadth of the rectangle whose area is given by 4a^2+4a-3
Answers
Answered by
3
Answer:
(2a-1)(2a+3)
Step-by-step explanation:
4a²+4a-3
=4a²+6a-2a-3
=2a(2a-3)-1(2a+3)
=(2a-1)(2a-+3)
Therefore, the length is (2a+3) and the breadth is (2a-1)
Answered by
1
Answer:
Area of the rectangle=l.b
4a²+4a-3=l.b
4a²+6a-2a-3=l.b
(4a²+6a)-(2a+3)=l.b
2a(2a+3)-1(2a+3)=l.b
(2a-1)(2a+3)=l.b
Therefore, suppose l=(2a-1),
b=(2a+3)
Therefore,2a-1=0
2a=1
a=1/2
b=2a+3
2a+3=0
2a=-3
a=-3/2
Now, length=1/2, breadth=-3/2
Step-by-step explanation:
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