give possible expression for the length and breadth of the triangle which has area a^2+6a+8
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Answered by
5
Heya !!
Area = a²+6a + 8
=> a² + 2a + 4a + 8
=> a ( a + 2 ) + 4 ( a + 2 )
=> ( a + 2 ) ( a + 4 )
-----------------------------------------
Area of rectangle = L × B
a² + 6a + 8 = ( a + 2 ) ( a + 4 )
Hence,
Length = a+ 4 and Breadth = a +2
Area = a²+6a + 8
=> a² + 2a + 4a + 8
=> a ( a + 2 ) + 4 ( a + 2 )
=> ( a + 2 ) ( a + 4 )
-----------------------------------------
Area of rectangle = L × B
a² + 6a + 8 = ( a + 2 ) ( a + 4 )
Hence,
Length = a+ 4 and Breadth = a +2
Answered by
1
the above shows the expression for l &b
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