give possible expressions for length and breadth of rectangle whose area is given by 4a2+4a-3
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Answered by
274
area of rectangle is= length X breadth
so it length and breadth can be factor of this expression.
so length can be :(2a+3)
breadth can be :(2a-1)
so it length and breadth can be factor of this expression.
so length can be :(2a+3)
breadth can be :(2a-1)
pls can you say from which keyboard u wrote a square and all those
in app or desktop version of this app,you will found √x or equation symbol,from there you can write all those expression
Answered by
81
area of rectangle = 4a²+4a-3
4a²+4a-3 = l×b
4a²+6a-2a-3=l×b
2a(2a+3)-1(2a+3) = l×b
(2a-1)(2a+3)=l×b
a=1/2 or -3/2 but length or breadth can't be negative
so A = 1/2
now putting a= 1/2
4×1/4 + 4×1/2-3=l×b
0 = l×b
4a²+4a-3 = l×b
4a²+6a-2a-3=l×b
2a(2a+3)-1(2a+3) = l×b
(2a-1)(2a+3)=l×b
a=1/2 or -3/2 but length or breadth can't be negative
so A = 1/2
now putting a= 1/2
4×1/4 + 4×1/2-3=l×b
0 = l×b
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