Question

Give possible expressions for the length and breadth of each of the following, in which their areas are given

Answer 1

Step-by-step explanation:

Area=25a

2

−35a+12

⇒ 25a

2

−15a−20a+12

⇒ 5a(5a−3)−4(5a−3)

⇒ (5a−3)(5a−4)

Hence, Area=(5a−3)(5a−4)

We know, Area=Length×breadth

Hence, there are two possibilities

Case1:Length=(5a−3) and Breadth=(5a−4)

Case2:Length=(5a−4) and Breadth=(5a−3)

(ii) Area=35y

2

+13y−12

⇒ 35y

2

+28y−15y−12

⇒ 7y(5y+4)−3(5y+4)

⇒ (5y+4)(7y−3)

Hence, Area=(5y+4)(7y−3)

We know, Area=Length×breadth

Hence, there are two possibilities

Case1:Length=(5y+4) and Breadth=(7y−3)

Case2:Length=(7y−3) and Breadth=(5y+4)

ooppsie

Answer 2

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i] area = 25a² - 35a + 12

factorise the equation~

By splitting the middle term.

25a²- 15a+ 20a + 12

5a(5a-3) - 4(5a-3)

(5a-3) (5a-4)

Hence area = (5a-3)(5a-4)

Area = length×breadth.

Therefore, there are two possibilities.

Case 1 :

length = 5a-3, breadth = 5a-4

Case 2 :

length = 5a-4, breadth = 5a-3