give possible expressions for the length and breadth of the rectangle whose area is given by 4a square+4a-3
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Answered by
4
Answer:
- 4a square+4a-3
- 4a square+4a-34a sq.-2a+6a-3
- 4a square+4a-34a sq.-2a+6a-32a(2a-1)+3(2a-1)
- 4a square+4a-34a sq.-2a+6a-32a(2a-1)+3(2a-1)(2a-1)(2a+3).
Answered by
5
hi mate,
solution:
Factoring 4a²+4a-3
4a² - 2a + 6a - 3
Step-1 : Add up the first 2 terms, pulling out like factors :
2a • (2a-1)
Add up the last 2 terms, pulling out common factors :
3 • (2a-1)
Step-2 : Add up the four terms of step 1 :
(2a+3) • (2a-1)
Which is the desired factorization
Final result :
(2a - 1) • (2a + 3)
length = (2a - 1) and breadth = (2a + 3)
or a = 1/2 and a = 3/2
i hope it helps you.
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