Question

Give possible expressions for the length and breadth of the rectangle whose area is

4a^2 + 4a - 3 ​

Answer 1

Step-by-step explanation:

$\huge\mathbb\red{SOLUTION :-}$

4a² + 4a - 3

4a² + 4a - 3

4a² - 2a + 6a - 3

2a ( 2a - 1 ) + 3 ( 2a - 1 )

( 2a - 1 ) ( 2a + 3 )

The given polynomial is area of rectangle

l × b = ( 2a - 1 ) ( 2a + 3 )

l = 2a - 1

b = 2a + 3

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Answer 2

${4a}^{2} + 4a - 3 \\ {4a}^{2} + 6a - 2a -3 \\ 2a(2a + 3) - 1(2a + 3) \\ (2a - 1)(2a + 3)$

The length and breadth of the rectangle are (2a-1) & (2a+3)

HOPE IT HELPS YOU!!!

PLZ MARK BRAINLIEST..