Question

Give proof.

Please answer as soon as possible :)​

Answer 1

Answer:

ANSWER PROVED AT END...

Step-by-step explanation:

************ HEY DEAR **************

HERE IS YOUR ANSWER.....

SIN (90 - A) = COS A

COS(90 - A) = SIN A

=> NOW PUT THE VALUES IN GIVEN QUESTION...

LEFT HAND SIDE:

   SIN A / COS A    +     COS A / SIN A

 TAKE L.C.M

  {SIN^2 A + COS^2 A/ (SINA *COS A)}

 WE KNOW,

 SIN^2A + COS^2A = 1

{ 1/(SINA*COSA)}

=> RIGHT HAND SIDE

   SEC(90 -A ) = COSEC A

   COSEC (90 -A ) = SEC A

PUT THE VALUES...

    COSEC A * SEC A

   {1 / (SINA* COSA)}

SO,

BOTH SIDES ARE EQUAL HENCE PROVED.....

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HOPE IT HELPS YOU...

THANKS..

^_^