Give proofs that cyclic quadrillateral's oppsite angle's be 180'
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Theorem Statement: The sum of the opposite angles of a cyclic quadrilateral is 180°.
Given: A cyclic quadrilateral ABCD where O is the center of a circle.
Construction: Join the line segment OB and OD. ...
∠BAD + ∠BCD = 180o ...
∠ABC + ∠ADC = 180o
Hence proved, that the sum of opposite angles of a cyclic quadrilateral is 180°
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