GIVE PROPER STEP BY STEP ANSWER PLEASE.
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Hey frnd here is ur solution
Let two roots be x and y
Given x - y = 3
x-3= y......(1)

put the value of y in this equation

Hope it helps u
Plz mark it brainliest
Let two roots be x and y
Given x - y = 3
x-3= y......(1)
put the value of y in this equation
Hope it helps u
Plz mark it brainliest
ash6129:
THIS ANSWER IS CORRECT BUT NOT SUFFICIENT YARR.
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