Physics, asked by zubajalgirli, 1 year ago

give reason curved roads are banked

Answers

Answered by kokan6515
1
Roads r banked so that vehicle can feel centripetal force which helps vehicle to move on mountainous roads

kokan6515: becoz most of banked roads r found on hilly areas
24khanak: no
24khanak: every turn is banked
24khanak: but we do not recognise it because the angle of banking is too less
kokan6515: that the thing i want to say
24khanak: but still they are banked
siri110998: most circular roads are banked due to the basic reason that while driving any vehicle wen u turn the vehicle to one side it tends to skid in the outward direction wich is because of the centripetal force acting outwards opposite in the direction of the turn, here banking helps by inc the friction caused by mg
24khanak: hmm
24khanak: correct
24khanak: i think my answer says the same.
Answered by 24khanak
2
consider a vehicle of mass 'm' moving with a velocity 'v' and making a turn on circular path of radius 'r'. the external forces acting on the vehicle are :-
1. weight=mg
2. normal contact force= N
3. friction = f
we need to keep in mind that,
> N is vertically upwards
> f is only horizontal force acting towards the centre
> f is self adjustable
> tyres have a tendency to skid outwards and therefore, to avoid skidding friction force acts towards centre.
thus for a safe turn,
  v^{2} /r = f/m
or,  f=m v^{2} /r
since there is a limit to the magnitude of frictional force, it cannot exceed μN where μ is coefficient of friction.
so, for vertical equilibrium, 
N= mg 
so that,
    f \leq   μ mg
then, for a safe turn, 
 m v^{2}/r  \leq μmg
or, μ \geq  v^{2} /rg

surface of road makes an angle θ with horizontal throughout the turn. N makes an angleθ with vertical. At the correct velocity the horizontal component of N is sufficient to produce the acceleration toward the centre and the self adjustable frictional force keeps the value zero. 
Applying newtons second law along the radius and first law in the vertical direction,
N sinθ= m v^{2}/r
⇒ N cosθ = mg 
gives, 
tanθ= v^{2}/rg
θ depends upon velocity of the vehicle as well as on the radius of the turn.
roads are banked for the average expected velocity of the vehicle.
HOPE IT HELPED YOU ENOUGH. NONE OF THIS WAS COPIED. YOU CAN EVEN CHECK ON NET TO FIND OUT. ITS MY OWN ANSWER. PLEASE MARK AS BRAINLIEST. PLEASE PLEASE PLEASE....

24khanak: plz note that m[tex]v^{2}/r [/tex] is nothing but mv^2/r
duragpalsingh: Good Answer!
24khanak: tnx
24khanak: please rate my answer
duragpalsingh: :)
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