Give reason of the following
1- why do we fall in a bus when the breaks of the bus are applied suddenly?
2- why the gun recoils when a bullet is fired from it?
3: tow bodies of different masses placed on the smooth surface are acted upon by a force of magnitude 10N. What do you think will happen to the acceleration of this bodies when the forces are applied? Give reason for your answer.
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Answered by
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Answer:
Here you go!
Explanation:
1) When breaks are applied to bus, the bus will start slowing down, but because no force has been applied on the passenger, it will try to move with the same velocity as earlier, because it doesnt like a change in its motion (velocity).
2)Gun recoil back when a bullet is fired from it due to principle of conservation of linear momentum.The backward recoil gun momentum balances the foreward bullet momentum to maintain zero total momentum.As the mass of bullet is small its velocity is very large while the mass of gun is large so its velocity is small in opposite direction to the bullet results in recoiling.
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Answered by
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1.In a moving bus, a passenger moves with the bus due to inertia of motion. As the driver applies brakes, the bus comes to rest. But, the passenger tries to maintain to inertia of motion. ... Hence, the passenger tends to fall backwards when the bus accelerates forward.
2. When a bullet is fired from a gun, the gun exerts a force on the bullet in the forward direction. This is force is called as the action force. The bullet also exerts an equal and opposite force on the gun in the backward direction. Therefore a gun recoils when a bullet is fired from it.
3. v(^_^v)♪
I’m not so sure about the third answer.
2. When a bullet is fired from a gun, the gun exerts a force on the bullet in the forward direction. This is force is called as the action force. The bullet also exerts an equal and opposite force on the gun in the backward direction. Therefore a gun recoils when a bullet is fired from it.
3. v(^_^v)♪
I’m not so sure about the third answer.
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