Chemistry, asked by khairaparam8415, 1 year ago

Give reasons : (i) acetylation of aniline reduces its activation effect. (ii) ch3nh2 is more basic than c6h5nh2 . (iii) although –nh2 is o/p directing group, yet aniline on nitration gives a significant amount of m-nitroaniline. 22. Ûúö¸þö ¤üßוö‹ : 1 × 3 = 3 (i) ÿöö¯ößµö ã£öö×µöÿ¾ö h2o ãöê h2 te ÿöûú ûú´

Answers

Answered by pickname90
6
Give reasons : (i) acetylation of aniline reduces its activation effect. (ii) ch3nh2 is more basic than c6h5nh2 . (iii) although –nh2 is o/p directing group, yet aniline on nitration gives a significant amount of m-nitroaniline. 22. Ûúö¸þö ¤üßוö‹ : 1 × 3 = 3 (i) ÿöö¯ößµö ã£öö×µöÿ¾ö h2o ãöê h2 te ÿöûú ûú´

Ans. (a) Because with acetylation of aniline is result in decrease of electron density on nitrogen so activation effect reduces.

 

(b) CH3NH2 is more basic than C6H5NH2because of positive I effect.

 

(c) Although amino group is o, p- directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline: Nitration is carried out in an acidic medium. In an acidic medium, aniline is protonated to give anilinium ion (which is meta-directing). For this reason, aniline on nitration gives a substantial amount of m-nitroaniline.

SO MARK AS BRAINIEST PLEASE.
Similar questions