give reasons why p of x is equal to X square + 1 does not have zeros and give two examples of this type of polynomial
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Hi ,
p( x ) = x² + 1
p( x ) never becomes zero for any real value of x.
Therefore , p( x ) doesn't have zeros .
example :
1 ) if x = 2 ,
p( 2 ) = 2² + 1 = 5
p( 2 ) ≠ 0
2 ) if x = -2
p( -2 ) = ( -2 )² + 1 = 4 + 1 = 5
p( -2 ) ≠ 0
for all real values of x we get a positive
number. which is greater than zero.
I hope this helps you.
:)
p( x ) = x² + 1
p( x ) never becomes zero for any real value of x.
Therefore , p( x ) doesn't have zeros .
example :
1 ) if x = 2 ,
p( 2 ) = 2² + 1 = 5
p( 2 ) ≠ 0
2 ) if x = -2
p( -2 ) = ( -2 )² + 1 = 4 + 1 = 5
p( -2 ) ≠ 0
for all real values of x we get a positive
number. which is greater than zero.
I hope this helps you.
:)
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