Math, asked by pavanssai2002, 1 year ago

give reasons why p of x is equal to X square + 1 does not have zeros and give two examples of this type of polynomial

Answers

Answered by mysticd
2
Hi ,

p( x ) = x² + 1

p( x ) never becomes zero for any real value of x.

Therefore , p( x ) doesn't have zeros .

example :

1 ) if x = 2 ,

p( 2 ) = 2² + 1 = 5

p( 2 ) ≠ 0

2 ) if x = -2

p( -2 ) = ( -2 )² + 1 = 4 + 1 = 5

p( -2 ) ≠ 0

for all real values of x we get a positive

number. which is greater than zero.

I hope this helps you.

:)
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