Question

give right answer don't spam .​

Answer 1

Answer:

3 hydroxy-2 methlylpent-4-enoic acid

Explanation:

carboxylic functional group should be given mere priority among all others which are present,so we have to start numbering from -COOH group,and the longest chain is of 5 carbons and there is a hydroxy group on 3rd carbon and the is a double bond(-ene functional group) on 4th carbon.so the answer is 1st option.

Answer 2

Answer:

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