Question

give sin A=12/37, find cos A and tan A​

Answer 1

Answer:

$\cos( \alpha ) = \frac{35}{37} \\ \\ \\ \tan( \alpha ) = \frac{12}{37}$

Explanation:

$\sin( \alpha ) = \frac{12}{37} \\ \\ p = 12 \: \: \: \: h = 37\: \\ \\ b = \sqrt{ {37}^{2} - {12}^{2} } = \sqrt{(37 - 12)(37 + 12)} \\ \\ = \sqrt{25 \times 49} \\ \\ = 5 \times 7 \\ \\ = 35 \\ \\ therefore \: \: \: \cos( \alpha ) = \frac{35}{37} \\ \\ \\ \tan( \alpha ) = \frac{12}{37}$