Question

Give solution of question no 14in full detail.

Answer 1

when we divide x3-3√5x2+13x-3√5 by x-√5

then we get the remainder 0 and quetiont x2-2√5+3.

it is expressed in the form of division algorithm.

then factorise the x2-2√5+3

p(x) = x2-2√5+3

a = 1 ,b = -2√5 , c = 3

D = b2-4ac

D = (-2√5)^2-4 . 1 . 3

D = 20-12 = 8

by quadratic formula,

x = -b+-√D/2a

x = -(-2√5)+-√8/2 . 1

x = 2√5+-2√2/2

x = 2(√5+-√2)/2

x = √5+-√2

therefore the other zeros are √5+√2 and √5-√2. is the answer.