Chemistry, asked by jayakulpreet, 1 year ago

Give some examples on enthalpies of combustion, fusion, sublimation, atomization, and neutralization(no spam)..

Answers

Answered by HR123
1
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• Examples of Sublimation:

1. "Dry ice" or solid carbon dioxide sublimes.

2. Snow and ice can sublime in the winter months without melting.

3. Moth balls sublime

4. Frozen foods will sublime and you will find ice crystals inside of the box or bag.
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•For example: atomization of methane molecule.

CH4(g) → C (g) + 4H (g) ; ΔHa= 1665.0 kJ per mol

example: atomization of dihydrogen molecule.

H2 (g) → 2H (g); ΔHa= 435.0 kJ per mol
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•EXAMPLE OF Neutralization

NaOH+H2SO4 --------- Na2SO4+H2O
NaOH + HCl ------- NaCl+ H20
Mg(OH)2 (s) + 2 HCl (aq) > MgCl2 (aq) + 2H2O (l) 
 H2SO4 + 2 NH4OH --> (NH4)2SO4 + 2 H2O 
 Ca(OH)2 + H2CO3 --> CaCO3 + 2 H2O 
 2 NaOH + H2CO3 --> N2CO3 + 2 NaOH 
 HNO3 + KOH --> KNO3 + H2O 
 HCl + NaHCO3 --> NaCl + H2O + CO2 
 H3PO4 + 3 NaOH --> Na3PO4 + 3H20 
 HF + NH3 → NH4F
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• EXAMPLES OF Enthalpies Of Combustion

Given a simple chemical equation with the variables A, B and C representing different compounds:

A+B⇋CA+B⇋C

and the standard enthalpy of formation values:

ΔHfo[A] = 433 KJ/molΔHfo[B] = -256 KJ/molΔHfo[C] = 523 KJ/mol

the equation for the standard enthalpy change of formation is as follows: 

ΔHreactiono = ΔHfo[C] - (ΔHfo[A] + ΔHfo[B])

ΔHreactiono = (1 mol)(523 kJ/mol) - ((1 mol)(433 kJ/mol) + (1 mol)(-256 kJ/mol)\)

Because there is one mole each of A, B and C,  the standard enthalpy of formation of each reactant and product is multiplied by 1 mole, which eliminates the mol denominator:

ΔHreactiono = 346 kJ

The result is 346 kJ, which is the standard enthalpy change of formation for the creation of variable "C".

The standard enthalpy of formation of a pure element is in its reference form its standard enthalpy formation is zero.
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