Question

give some formulae in trigonometry

Answer 1

✔️✔️✔️Some important formulae from the chapter trigonometry are :-

1) cos2 A + sin2 A = 1.

2) cos2 A =1 - sin2 A.

3) sin2 A =1 - cos2 A.

4) sec2 A - tan2 A = 1.

5) 1 + tan2 A = sec2 A.

 6) tan2 A = sec2 A – 1.

7) cosec2 A - cot2 A = 1.

8) cot2 A + 1 = cosec2 A.

9) cot2 A = cosec2 A – 1 .

10) sec A - tan A = 1sec A + tan A

11) cosec A - cot A = 1cosec A + cot A

✔️✔️✔️where  0  is the measure of the particular angle .

sin 0 =  P/ H 

cos 0 = B / H 

tan 0 =  P / B 

cot 0 = B / P 

sec 0 =  H / B 

cosec 0 =  H /  P

⭕️P= perpendicular of triangle.

 ⭕️ B = base of triangle

⭕️  H = hypotenuse of triangle.

$\huge\bf{\boxed {\red{\mathfrak{thank \: you :)}}}}$

Answer 2

Trigonometry Formulas :

• sinØ = P/H

• cosØ = B/H

• tanØ = P/B

• cosecØ = H/P

• secØ = H/B

• cotØ = B/P

____________________________

》 sin²Ø + cos²Ø = 1

› sin²Ø = 1 - cos²Ø

› cos²Ø = 1 - sin²Ø

》 1 + cot²Ø = cosec²Ø

› cot²Ø = cosec²Ø - 1

› cosec²Ø - cot²Ø = 1

》 1 + tan²Ø = sec²Ø

› tan²Ø = sec²Ø - 1

› sec²Ø - tan²Ø = 1

____________________________

• sinØ = 1/cosecØ

coecØ = 1/sinØ

• cosØ = 1/secØ

secØ = 1/cosØ

• tanØ = 1/cotØ

cotØ = 1/tanØ

____________________________

• At 0°

• sinØ = 0

• cosØ = 1

• tanØ = 0

• cosecØ = Not defined

• secØ = 1

• cotØ = Not defined

• At 30°

• sinØ = 1/2

• cosØ = √3/2

• tanØ = 1/√3

• cosecØ = 2

• secØ = 2/√3

• cotØ = √3

• At 45°

• sinØ = 1/√2

• cosØ = 1/√2

• tanØ = 1

• cosecØ = √2

• secØ = √2

• cotØ = 1

• At 60°

• sinØ = √3/2

• cosØ = 1/2

• tanØ = √3

• cosecØ = 2/√3

• secØ = 2

• cotØ = 1/√3

• At 90°

• sinØ = 1

• cosØ = 0

• tanØ = Not defined

• cosecØ = 1

• secØ = Not defined

• cotØ = 0

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