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From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the
same height and same diameter is hollowed out. Find the total surface area of the
remaining solid to the nearest cm2.
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Answer:
iven :
radius (r)=
2
diameter
=
2
1.4
=0.7 cm
height (h)=2.4 cm
Total surface area= surface area of cylinder+ surface area of cone−2(surface area of above circle).
=2πrh+2πr
2 +πr 2 +πr h 2 +r
2 −2πr 2 =2πrh+πr h
2+r
2 +πr
2 =π(2rh+r 2+r h 2 +r 2)
= 7 22
(2×0.7×2.4+(0.7)
2 +0.7
(0.7)
2 +(24) 2 )
= 7 22
(3.36+0.49+1.75)
=7 22 (5.6)
Total surface area=17.6cm
2 .
Hence, this is the answer.
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