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Answer 1

Answer:

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Answer 2

Answer:

(i)∠DCE=∠ABC=40°(Corresponding angle)

∠DCE+∠ACD+∠ACB=180° (Straight line)

40°+70°+y=180°

therefore, y=70°

∠ABC+∠ACB+∠BAC=180° (Sum of interior angles of triangle)

40°+70°+x=180°

therefore, x=70°

(ii) ∠PRQ+∠PRS=180° (Straight line)

60°+x=180°

therefore, x=120°

∠PQR+∠QPR+∠PRQ=180°

50°+y+60°=180°

therefore, y=70°

(iii) 30°+50°+z°=180° (Sum of interior angles of triangle)

therefore, z=100°

z+x=180° (Straight line)

therefore, x=80°

x+45°+w=180° (Sum of interior angles of triangle)

therefore, w=55°

50°+w+y=180° (Straight line)

therefore, y=75°

(iv) ∠x=80° (Vertically opposite angles)

50°+80°+y=180° (Sum of interior angles of triangle)

therefore, y=50°