Question

give tha electronic configuration of cl-ion​

Answer 1

Answer:

electronic configuration of Cl is 2,8,7

Explanation:

hope it help you

Answer 2

The electronic configuration of $Cl^{-}$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{5}$.

Explanation:

Bohr and Bury described the arrangement and distribution of electrons in distinct orbits. Electronic configuration of any element shows how the electrons are arranged in the shells present around the nucleus of the element. Shells can hold $2n^{2} electrons$ ; where n is the shell number.

K shell  $2n^{2}\ ; n = 1; 2*1^{2} = 2\ electrons$

L shell $2n^{2}\ ; n = 2; 2*2^{2} = 8\ electrons$

Every shell has orbitals and every orbital has a fixed number of electrons that it can accommodate.

- s orbital: $2\ electrons$

- p orbital: $6\ electrons$

- d orbital: $10\ electrons$

- f orbital: $14\ electrons$

Chlorine has $17\ electrons.$

As, The first shell will have $2\ electrons$, the second shell $8\ electrons$, and the third shell $7\ electrons$.

Filling the orbitals in the sequence s, p, d and f. Starting with s orbital for every new shell.

So, electronic configuration of $Cl^{-}$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{5}$.