Question

give that 2 is a root of the equation 3 x square - p * (X + 1) = 0 and that the equation pX square - q X + 9 = 0 has equal roots find the values of P and Q​

Answer 1

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FIRST FINDING THE VALUE OF p

substitute 2 in place of x

$3 \times {2}^{2} - p(2 + 1) \\ 12 - 3p = 0 \\ - 3p = - 12 \\ p = 4$

${\boxed{p=4}}$

FINDING THE VALUE OF q

substituting the value of x and p

$4 \times {2}^{2} - q \times 2 + 9 = 0$

$16 - 2q + 9 = 0 \\ 25 + - 2q = 0 \\ 2q = 25 \\ q = 25 \div 2$

${\boxed{q=25/2}}$

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HOPE IT HELPS YOU ❤✨

Answer 2

Answer:

hope this helps :)

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