Give that √3 is irrational, prove that 5√3-2 is an irrational number?
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Step-by-step explanation:
Let 5√3-2 be rational number.
rational numbers are in the form of P/q.
so, 5√3-2=p/q
=> 5√3=p/q+2
=> 5√3=p+2q/q.
=> √3=P+2q/5q.
Given.that √3 is irrational number.
so, p+2q/5q is also irrational.
Therefore, our assumption is wrong that 5√3-2 is rational.
5√3-2 is an irrational number.
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