Question

Give that an electric field of 10N/C has a northward direction and another electric field of 10N/C has a eastward direction, what are the magnitude and direction of the superposition of these two electic field?​

Answer 1

Answer:

Electric field =10N/C

Vertically downward direction electric potential as one goes through h=50cm =50×10−2m

Now, V=E/d

=10/50×10−2=5100=20J