Question

Give that equation of the straight line with gradient 2 that passes through (1,4) and (2,6).​

Answer 1

Step-by-step explanation:

The slope-intercept equation of a line :

y

=

m

x

+

c

Here

m

=

slope

c

=

y

-intercept

Therefore, the required equation is:

y

=

2

x

+

c

Putting the point

(

1

,

4

)

in it as it lies on line, we get:

4

=

2

+

c

Therefore

c

=

2

So

y

=

2

x

+

2

is the required equation