Question

give that the zeroes of the cubic polyomial x3↑-6x2↑+3x+10 are of the form a , a+b, a+2b for some real number a and b , find the values of a and b as well as the zeroes of the given polynomial

Answer 1

Answer:

Let f(x) = x2 + 7x + 10 By splitting the middle term, we get f(x) = x2 + 5x + 2x + 10 [∵ 7 = 2 + 5 and 2×5 = 10] = x(x + 5) + 2(x + 5) = (x + 2) (x + 5) On putting f(x) = 0 , we get (x + 2) (x + 5) = 0 ⇒ x + 2 = 0 or x + 5 = 0 ⇒x = – 2 or x = – 5 Thus, the zeroes of the given polynomial x2 + 7x + 10 are – 2 and – 5Read more on Sarthaks.com - https://www.sarthaks.com/921178/find-zeroes-thequadratic-polynomials-verify-relationship-between-zeroes-coefficients

Step-by-step explanation:

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