Give that under root 2 is irrational, prove that (5+3 under root 2 ) is an irrational number.
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5+3ROOT 2 IS IRRSTIONAL
5+3ROOT 2 = a/b
3root2=a/b-5
3root2=a-5b/b
root2 =a-5b/3b
root2 is irrational but a-5b/3b is rational...
5+3ROOT 2 = a/b
3root2=a/b-5
3root2=a-5b/b
root2 =a-5b/3b
root2 is irrational but a-5b/3b is rational...
Answered by
0
!!! Hi friends !!!
let 5+3√2 be rational
5+3√2 = a / b [where a and b are co prime nos]
3√2 = a / b - 5
3√2 = a- 5b / b
√2 = a- 5b / 3b
∴ a- 5b / 3b is rational
∴ √2 is also rational
but it is given that √2 is irrational
this contradiction has arisen because of our wrong assumption that 5 + 3√2 is rational
∴ 5 + 3√2 is irrational
Hence proved.......... ;D
***************************************************************************************
Hope this helps.................. :D
let 5+3√2 be rational
5+3√2 = a / b [where a and b are co prime nos]
3√2 = a / b - 5
3√2 = a- 5b / b
√2 = a- 5b / 3b
∴ a- 5b / 3b is rational
∴ √2 is also rational
but it is given that √2 is irrational
this contradiction has arisen because of our wrong assumption that 5 + 3√2 is rational
∴ 5 + 3√2 is irrational
Hence proved.......... ;D
***************************************************************************************
Hope this helps.................. :D
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