give the acidic strength ortho para and meta position
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ortho>pera>meta
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sapna2000:
its ortho meta then para
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Basically at first compound ...we can see that ...IT WILL HAVE EFFECT OF THE STERRIC HINDRANCE ON IT ......SO ITS SLIGHTLY UNSATBLE .....
At the Meta Position .....the CH3 HAS PLUS INDCTIVE EFFECT BUT .THAT POSITION IS A RING DEACTIVATING POSITION SO NOT MUCH BENIFIT OF ACIDITY. ...
BUT AT THE PARA POSITION. ..we can see that there will be pushing effect of the CH3...also .....the H in the CARBONYL BOND will be more acidic due to the Electronegativity and also the after the proton donation or removal of the Alpha hydrogen the ....the carbonion will be in Resonance .....
_____________________________________
HOPE MIGHT IT HELP
Here is Your ANSWER _______
Basically at first compound ...we can see that ...IT WILL HAVE EFFECT OF THE STERRIC HINDRANCE ON IT ......SO ITS SLIGHTLY UNSATBLE .....
At the Meta Position .....the CH3 HAS PLUS INDCTIVE EFFECT BUT .THAT POSITION IS A RING DEACTIVATING POSITION SO NOT MUCH BENIFIT OF ACIDITY. ...
BUT AT THE PARA POSITION. ..we can see that there will be pushing effect of the CH3...also .....the H in the CARBONYL BOND will be more acidic due to the Electronegativity and also the after the proton donation or removal of the Alpha hydrogen the ....the carbonion will be in Resonance .....
_____________________________________
HOPE MIGHT IT HELP
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