Chemistry, asked by sapna2000, 1 year ago

give the acidic strength ortho para and meta position

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Answered by Gauravmj
0
ortho>pera>meta
your answer is above

sapna2000: its ortho meta then para
Gauravmj: how can u explain
sapna2000: explained where u commented how
Answered by Anonymous
2
Hola User .....___________________

Here is Your ANSWER _______

Basically at first compound ...we can see that ...IT WILL HAVE EFFECT OF THE STERRIC HINDRANCE ON IT ......SO ITS SLIGHTLY UNSATBLE .....

At the Meta Position .....the CH3 HAS PLUS INDCTIVE EFFECT BUT .THAT POSITION IS A RING DEACTIVATING POSITION SO NOT MUCH BENIFIT OF ACIDITY. ...

BUT AT THE PARA POSITION. ..we can see that there will be pushing effect of the CH3...also .....the H in the CARBONYL BOND will be more acidic due to the Electronegativity and also the after the proton donation or removal of the Alpha hydrogen the ....the carbonion will be in Resonance .....



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Gauravmj: yeah I have precise reasons for it
Gauravmj: but i can't explain them here
Gauravmj: I can click it and send u
sapna2000: ok
Gauravmj: but how?
Gauravmj: don't mind I'm serious
sapna2000: just post them in other posts
Gauravmj: ok I'll try
Gauravmj: in morning
Gauravmj: good night
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