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pq=pr. (tangent are equal to external point)
<prq is an isosceles triangle
anlge prq =angle pqr
let angle prq be x
in trianle prq
<prq +<pqr+<qrp=180
x+x+30=180
2x=180-30
2x=150
x=150/2
x=75
therefor
<prq=<pqr=75
<prq is an isosceles triangle
anlge prq =angle pqr
let angle prq be x
in trianle prq
<prq +<pqr+<qrp=180
x+x+30=180
2x=180-30
2x=150
x=150/2
x=75
therefor
<prq=<pqr=75
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