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i am sorry... for answering only the first one
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diameter of inner part = 60m
radius= 30m
diameter of whole track = 80m
radius = 40m
(i) distance around the inner track along its inner edge = 106+106+2pir
106+106+2*(22/7)*30
212+(1320/7) = (1484+1320)/7
2804/7 m
(ii) area of the track = 2*l*b + pi(R square - r square)
= 2*106*10 + (22/7)( 40 square - 30 square )
= 2120 + (22/7) (1600-900)
= 2120 + (22/7)(700)
= 2120 + 2200
= 4320 msquare
radius= 30m
diameter of whole track = 80m
radius = 40m
(i) distance around the inner track along its inner edge = 106+106+2pir
106+106+2*(22/7)*30
212+(1320/7) = (1484+1320)/7
2804/7 m
(ii) area of the track = 2*l*b + pi(R square - r square)
= 2*106*10 + (22/7)( 40 square - 30 square )
= 2120 + (22/7) (1600-900)
= 2120 + (22/7)(700)
= 2120 + 2200
= 4320 msquare
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