Question

Give the Answer if 3+4=19 , 5+6=41, 1+3=???

Answer 1

The values of the given series 3+4 = 19, 5+6 = 41, 1+3 = ??? is 7.

To find:

Give the Answer if 3+4 = 19, 5+6 = 41, 1+3 = ?

Solution:

Given: 3+4 = 19, 5+6 = 41, 1+3 = ???

3+ 4 = 19

Now, $3+4=7 \text { and } 3 \times 4=12$. If we add 7 + 12, we get 19.

Hence, addition of two given numbers i.e. on L.H.S. + multiplication of given two numbers i.e. on L.H.S. = required answer on R.H.S.

Likewise, 5 + 6 = 41

$5+6=11 \text { and } 5 \times 6=30$. If we add 11 + 30, we get 41.

1+3 = ???

$\bold{1+3=4 \text { and } 1 \times 3=3}$. If we add 4 + 3, we get 7.

Hence, 1 + 3 = 7.  

Answer 2

If 3+4=19 , 5+6=41  then 1+3=7

Given:

3+4=19 , 5+6=41

To find:

1+3=?

Solution:

Formula of the Pattern:

If we closely observe these equations, we will observe a pattern in all the them which follows the following equation:

$a+b=(a+b)+(a \times b)$

Then the solution for the given is  

By following this rule, we can easily compute the value of 1+3.

$1+3=(1+3)+(1 \times 3)$

1+3=4+3=7  

Thus, 1+3 = 7 by following the rule mentioned above.

We can solve similar questions in the similar manner closely observing the pattern. By observing the pattern we can easily derive an expression that the equations are following.