Math, asked by sanu27937, 8 months ago

Give the answer.
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Answered by my8913842
0

F1(1,2,2),F2(2,1,2),F3(2,2,1)……3 ways.

Again F1(3,1,1),F2(1,3,1),F3(1,1,3)……3ways

Total number of ways =3+3=6 ways.

Answered by Anonymous
11

Answer:

F1(1,2,2),F2(2,1,2),F3(2,2,1)… …3 ways.

Again F1(3,1,1),F2(1,3,1),F3(1,1,3)… …3ways

Total number of ways =3+3=6 ways.

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