Physics, asked by aast70, 1 year ago

give the answer of 2(i)...(ii)..and (iii) and 3..(iii) plz give detailed answer​

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Answers

Answered by ssj96191
0

Answer:

Explanation:

2) I .Cos ^2 x=1-2sin^2x =2xos^2x-1

2) ll Sin^2 (ax+b) = -cos^2 (ax+b)/a +c .2sin(ax+b)

3) l. 2x cosx .-sinx

3)lll. Cos^2x.sinx^2= 2cosx.sinx^2*cosx^2.2sinx

Answered by Arceus11
1

2)

(i) Use chain rule.

d/dx cos²x= 2cosx × (-sinx)=-2sin2x.

(ii) Derivative= 2sin(ax+b)×cos(ax+b)×a

=asin(2(ax+b))

(iii) Derivative=cos(ax+b)²×{2(ax+b)}×a

=2a(ax+b)cos(ax+b)²

3)(iii) cos²xsin²x= (1-sin²x)(sin²x)=sin²x-sin⁴x

Derivative=2sinxcosx-4sin³xcosx

=sin2x-2sin²xsin(2x)

=sin(2x){1-2sin²x}

=sin(2x)cos(2x)

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