Question

Give the answer of the above question

Answer 1

Answer:

Explanation:

in the first case, he is initially at rest. therefore u or initial velocity =0. he attains a velocity of 6m/s in 30 secs. acceleration is the rate of change of velocity. therefore a=(6-0)/30 = 1/5 = 0.2 m/s². thus acceleration I. first case is 0.2 m/s².

in the second case he is initially moving at 6m/s and the velocity then decreases to 4 m/s in 5 seconds. therefore initial velocity or u = 6 and final velocity v =4. a or acceleration = (v-u)/t = (4-6)/5 = -2/5 = -0.4 m/s². thus we can say that in the second case acceleration is -0.4m/s² or the retardation is 0.4m/s². this is because the negative acceleration is called retardation.

hope it helps

plz mark as brainliest