Question

give the answer of the question attached

Answer 1

Answer:

+and-1

Step-by-step explanation:

The given quadratic equation is ax²+2x+a=0

and the roots are equal

Then,

to find the value of a

Here, a=a, b=2 and c=a

As we know that D=b²-4ac

Putting the value of a,b and c

we have,

=(2)²-4×a×a

=4-4a²

The given equation will have real and equal roots, if D>0.

4-4a²=0

4a²=4

a²=4/4

a=root1

a=1

Hence the value of a = +and-1