give the answer of this 4Q
Attachments:
Ivnat:
Hey buddy plz send whole fig
Answers
Answered by
0
In ΔABC,
∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property of a triangle)
⇒ ∠BAC + 69° + 31° = 180°
⇒ ∠BAC = 180° − 100º
⇒ ∠BAC = 80°
∠BDC = ∠BAC = 80° (Angles in the same segment of a circle are equal)
hope it's help you dear.....
:-)
thanks
∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property of a triangle)
⇒ ∠BAC + 69° + 31° = 180°
⇒ ∠BAC = 180° − 100º
⇒ ∠BAC = 80°
∠BDC = ∠BAC = 80° (Angles in the same segment of a circle are equal)
hope it's help you dear.....
:-)
thanks
Similar questions
Chemistry,
6 months ago
Math,
6 months ago
Geography,
6 months ago
Social Sciences,
11 months ago
Math,
1 year ago