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x + y = 18
x*y = 72
So we need whole number factors of 72 that fulfill those conditions.
Factors of 72:
1, 2, 3, 4, 6, 8, 9, 12, 18, 36, 72
Two of those numbers add up to 18 and multiply to make 72:
12 and 6
Let x = 12 and y = 6
x+y = 18
12+6 = 18
18 = 18
x*y = 72
12*6 = 72
72 = 72
So x = 12 and y = 6. Now substitute in the third equation:
(12)^2 + (6)^2 = 144 + 36 = 180
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