Question

Give the answer with a attachment and proper explanation so that I can understand ​

Answer 1

Answer:

Explanation:

Given:

If v be the velocity at a distance x then

$V=\frac{K}{X}$

But if $X=1, V=2$ then $K=2$

Hence:

$V=\frac{2}{X}$ but $V=\frac{DX}{DT}$

So $\frac{DX}{DT}=\frac{2}{X}$

Or xdx=2dt integrating both sides

x²/2=2t+C c=const of int.

Rearranging we get  

t=x²/4-C/2  

From the given data let at t1 x=1

t1=1/4-C/2

and at B x=2 hence

t2=4/4-C/2=1-C/2

So the the time taken from A to B is

t2-t1=1-1/4=3/4 sec=75sec

Thanks : ]