Math, asked by PURPLEARMYGIRL173, 18 days ago

give the answer with full solution !! ​

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Answers

Answered by pallavissanga
4

It is given that

Principal= 46875

Rate of interest = 4% p.a

(i) Interest for the first year= Prt/100

Substituting the values

=(46875×4×1)/100

= 1875

So the amount after the first year or principal for the second year= 46875+1875=48750

Here

Interest for the second year=(48750×4×1)/100= 1950

(ii) We know that

Amount at the end of second year = 48750+1950

= 50700

(iii) Interest for the third year =(50700×4×1)/100=2028

Answered by loganlevi2004
14

Step-by-step explanation:

(i) Principal for the first year = Rs 46875

Rate of interest = 4% per annum

Therefore,

Interest for the first year = Rs (46875 × 4 × 1) / 100

We get,

= Rs 46875 / 25

= Rs 1875

Hence, interest for the first year is Rs 1875

(ii) Amount at the end of first year

= Rs 46875 + Rs 1875

We get,

= Rs 48750

Principal for the second year = Rs 48750

Interest for the second year = Rs (48750 × 4 × 1) / 100

= Rs 48750 / 25

We get,

= Rs 1950

Amount at the end of second year = Rs 48750 + Rs 1950

We get,

= Rs 50700

Hence, the amount at the end of second year is Rs 50700

(iii) Principal for the third year = Rs 50700

Interest for the third year = Rs (50700 × 4 × 1) / 100

We get,

= Rs 507 × 4

= Rs 2028

Hence, the interest in the third year is Rs 2028

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