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Answers
It is given that
Principal= 46875
Rate of interest = 4% p.a
(i) Interest for the first year= Prt/100
Substituting the values
=(46875×4×1)/100
= 1875
So the amount after the first year or principal for the second year= 46875+1875=48750
Here
Interest for the second year=(48750×4×1)/100= 1950
(ii) We know that
Amount at the end of second year = 48750+1950
= 50700
(iii) Interest for the third year =(50700×4×1)/100=2028
Step-by-step explanation:
(i) Principal for the first year = Rs 46875
Rate of interest = 4% per annum
Therefore,
Interest for the first year = Rs (46875 × 4 × 1) / 100
We get,
= Rs 46875 / 25
= Rs 1875
Hence, interest for the first year is Rs 1875
(ii) Amount at the end of first year
= Rs 46875 + Rs 1875
We get,
= Rs 48750
Principal for the second year = Rs 48750
Interest for the second year = Rs (48750 × 4 × 1) / 100
= Rs 48750 / 25
We get,
= Rs 1950
Amount at the end of second year = Rs 48750 + Rs 1950
We get,
= Rs 50700
Hence, the amount at the end of second year is Rs 50700
(iii) Principal for the third year = Rs 50700
Interest for the third year = Rs (50700 × 4 × 1) / 100
We get,
= Rs 507 × 4
= Rs 2028
Hence, the interest in the third year is Rs 2028