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In Triangle ABC .
Angle ABC =90°
ANGLE ACB =45°
THEN 3rd angle =(180-90+90)°=45°
Therefore Triangle ABC is an isosceles Triangle.
Therefore Area =1/2×base×height=(1/2×8×8)cm^2=32cm^2
Angle ABC =90°
ANGLE ACB =45°
THEN 3rd angle =(180-90+90)°=45°
Therefore Triangle ABC is an isosceles Triangle.
Therefore Area =1/2×base×height=(1/2×8×8)cm^2=32cm^2
sankityadav5:
wrong answere
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