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6. Find the roots of the quadratic equation 6x-x-2=0?
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6x²-x-2 = 0
6x²-4x+3x-2 = 0
= 2x(3x-2)+1(3x-2) = 0
=> (3x-2)(2x+1) = 0
Either
3x-2=0
=> 3x = 2
=> x = 3/2
Or
2x+1 = 0
=> 2x = -1
=> x = -1/2
Therefore zeroes of 6x²-x-2 are 3/2 and -1/2
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