Question

Give the answers please

Answer 1

Here ,
side BC || side AD,
ADB=CBD
DBC=65°

Answer 2

Answer:

Step-by-step explanation:

Angle DBC = Angle ADB (Alternate

Interior angles)

So, angle DBC = 65°

In ∆DBC

Angle D +Angle B +Angle C= 180°

( A.S.P. of ∆)

Angle D + 65° + 50° = 180°

So Angle BDC = 65°

Angle DBA = Angle BDC= 65°

(Alt. Int. Angles)

In ∆ADB

Angle A +Angle D + Angle B=180°

Angle A + 65° + 65°= 180°

So Angle A=50°