Give the balance equation for lab preaperation of ammonia with excess of chlorine
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8NH3 [excess] + 3Cl2 → 6NH4Cl + N2.
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8NH3 + 3CI2------>6NH4CI+N2
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The answer of u r question is..✌️✌️
Ans:✍️✍️✍️✍️✍️✍️
8NH3 + 3CI2------>6NH4CI+N2
Hope it helps uu buddy!!❤️❤️
Thank you..☺️☺️
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