Question

give the balance equation of sodium propionates react with soda lime​

Answer 1

Answer:

C(2)H(5)COONa + NaOH ------> C(2)H(6) + Na(2)CO(3). This reaction proceeds with the application of heat; this type of reaction in which CO(2) molecule is removed from a carboxylic acid is called decarboxylation.

Answer 2

Answer:

CH3-CH2-COONa +NaOH=CH3-CH3 +Na2OH

Explanation:

please note that = sign symbolises catalyst cao when heated

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