give the brilliant answer and explain step by step I will mark you asbrilliant
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Step-by-step explanation:
Given
Angel BAE = 124°
Angel ECD = 108°
Angle BAE + Angle BAC = 180°(linear pair)
Angel BAC=180°-124°=56°
Angle ECD + Angle BCE= 180°
Angle BCE = 180°-108°=72°
In triangle BCA
By ASP ( angle sum property) of a triangle
a+b+c=180°
Angle BAC+ Angle BCE+ Angle ABC=180°
Angel ABC= 180°-(72°+ 56°)
Angle ABC = 180°-128°=52°
Hope this answer is helpful
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